3p^2+11p=-10

Solution for 3p^2+11p=-10 equation:

3p^2+11p=-10

We move all terms to the left:

3p^2+11p-(-10)=0

We add all the numbers together, and all the variables

3p^2+11p+10=0

a = 3; b = 11; c = +10;
Δ = b2-4ac
Δ = 112-4·3·10
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-1}{2*3}=\frac{-12}{6}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+1}{2*3}=\frac{-10}{6}
=-1+2/3
$